h^2=11^2+18^2

Solution for h^2=11^2+18^2 equation:

h^2=11^2+18^2

We move all terms to the left:

h^2-(11^2+18^2)=0

We add all the numbers together, and all the variables

h^2-445=0

a = 1; b = 0; c = -445;
Δ = b2-4ac
Δ = 02-4·1·(-445)
Δ = 1780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1780}=\sqrt{4*445}=\sqrt{4}*\sqrt{445}=2\sqrt{445}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{445}}{2*1}=\frac{0-2\sqrt{445}}{2}
=-\frac{2\sqrt{445}}{2}
=-\sqrt{445}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{445}}{2*1}=\frac{0+2\sqrt{445}}{2}
=\frac{2\sqrt{445}}{2}
=\sqrt{445}
$